How will you find the area of the geometric figure under description?

Draw it. Then break the trapezoid into two triangles and a rectangle. Solve for the first triangle, the second triangle, then find the area of the rectangle. Add the three areas up and you have your total area.

I'm not doing your basic math. You should be able to do this yourself. It isn't hard. And it's not about whether or not you'll use it in your future, it's about whether or not you have work ethic and the intelligence to solve stuff on your own. It doesn't matter if you're not a math person; what matters is if you're capable of doing simple things on your own, or if you need your mom to hold your hand all day and lead you to the bathroom because you don't want to look for it yourself.

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RE:

How will you find the area of the geometric figure under description?

ABCE is a trapezoid in which AB is parallel to CE.

AB = 15 cm

CE = 22 cm

Angle BCE = 33 degrees

AD is perpendicular to CE

Areas

Formulas and instructions for finding the areas of circles, kites, parallelograms, rectangles, rhombi, squares, trapezoids and oddly shaped geometric objects

Just scroll down or click on what you want and I'll scroll down for you!

area of a circle area of a kite area of a parallelogram

area of a rectangle area of a rhombus area of a square

area of a trapezoid area of an oddly shaped

geometric region

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The area of a circle:

circle graphic

Area = circle graphic

where r = the radius of the circle

and pi = 3.141592...

red line

The area of a kite:

To find the area of a kite, multiply the lengths of the two diagonals and divide by 2 (same as multiplying by 1/2):

Area of kite = (1/2)ab

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AB and CE are the bases, so you just need to figure out the height.

Triangle ACD is a right triangle. AD is the height. It is opposite the angle

CD = 1/2(CE - AB) = 1/2(22-15) = 7/2

tan(33) = AD/(7/2)

AD = (7/2)tan(33)

Area = 1/2(AB + CE)(AD) = 1/2(15 + 22)((7/2)tan(33))

If it is not an isosceles trapezoid, then the answer is not unique. Let us assume that it is an isosceles trapezoid. BD = 3.5 tan 33 = 2.2729. Hence area = (a+b)h/2 = (15+22)(2.2729)/2 = 42.0487 cm^2