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? asked in Science & MathematicsMathematics · 8 years ago

Solve the following simultaneous equations?

y=x^2+3x+2

y=2x+8

and

y-x^2-3x+2

y=x+1

With steps please

1 Answer

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  • 8 years ago
    Favorite Answer

    y=x^2+3x+2 and y=2x+8

    therefore x^2=3x+2 = 2x+8

    x^2+3x+2-2x-8 = 0

    x^2+x-6 = 0

    x^2+3x-2x-6 = 0

    x(x+3)-2(x+3) = 0

    (x+3)(x-2) = 0

    x+3 = 0 or x-2 = 0

    x = -3 or x = 2

    when x = -3, y = 2(-3)+8 = -6+8 = 2

    when x= 2, y = 2(2)+8 = 4+8 = 12

    solutions are {-3,2} and {2, 12}

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