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Parabola problem where the equation equals zero. pre calc Help solve please?
Find the foci, and asymptotes of the hyperbola with vertex at (0,-2) and (0,2).
(x^2)-(y^2)+4=0
2 Answers
- DWReadLv 78 years agoFavorite Answer
What parabola problem?
:::::
x² - y² + 4 = 0
x² - y² = -4
divide equation by righthand side
x²/(-4) - y²/(-4) = -4/(-4)
-x²/4 + y²/4 = 1
y²/2² - x²/2² = 1
y²/2² - x²/2² = 1 is the equation of a vertical hyperbola with
center (0, 0)
vertices (0, 0±2) = (0, -2) and (0, 2)
c² = 2² + 2²
c = 2√2
foci (0, 0±2√2) = (0, -2√2) and (0, 2√2)
asymptotes: y = ±x
- 4 years ago
ok, logA + logB = logC log(A*B) = logC So, AB = C log(3x-2) + log(x-a million) = log2x log[(3x-2)(x-a million)] = log2x (3x-2)(x-a million) = 2x 3x^2 - 5x + 2 = 2x 3x^2 - 7x + 2 = 0 (x - 2)(3x - a million) = 0 So x = 2 or x = a million/3
