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In right triangle HAR altitude AD is drawn to hypotenuse HR. If HD=12 and DR=15 find AH.?

please show work

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  • Anonymous
    8 years ago

    AD will divide the triangle HAR into 2 right triangles ADR and ADH.

    now, in triangle ADH cos(AHD) = 12/AH

    in triangle HAR cos(AHR) = AH/(12+15)

    = AH/27

    But, AHR = AHD, so, 12/AH = AH/27

    AH = 18

    :)

  • 8 years ago

    AH = 18

    triangles ARD and AHD are similar

    because both are similar to the bigger RHA

    for details watch this

    http://img15.imageshack.us/img15/8862/righttriangl...

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