Algebra II! Equations! HELP!?

(2) What you typed means 8x^2 + 6x = 0,

so x = 0 or x = 6/8 = 0.75

(1) What you typed here means

x^3 - 19x - 12 = 0.

Evidently x = -4 is a solution, so divide out the factor (x+4).

(x+4)(x^2-4x-3) = 0

The quadratic factor has the roots

x = 2 plus or minus (1/2)sqrt(16+12)

= 2 plus or minus sqrt(7)

So the three solutions are x = -4,

x = about 4.646, and x = about -0.646.

If the original equation really had a 3x^2 in it and not 3x,

that's an entirely different problem.

(4) (3x+10)^1/3 means (3x+10)/3 = x + (10/3). I'm SURE you didn't mean that.

Instead, you should've typed:

(3x+10)^(1/3) = -5

3x + 10 = (-5)^3 = -125

3x = -135

x = -45

(5) is so badly typed that I can't even be sure what it means,

but I guess it COULD mean

(2) [4^(1/3)] sqrt(x-11) = 6

[4^(1/3)] sqrt(x-11) = 3

[4^(2/3)] (x-11) = 9

x - 11 = 9 / [4^(2/3)]

x = 11 + (9/4)(cube root of 4) = about 14.572

(3) The way you typed this one, it means (1/4)x^3 = 27

x = (3) (cube root of 4) = about 4.762

If you meant x^(3/4) - 8 = 19,

then x^(3/4) = 27 and x = 81.

You need to study "order of operations" in Wikipedia.

3x - 8y = 4 2x - 6y = 2 Use one eqation to outline one variable in time period of the different. Then use this defition inthe first varibel to scrub up. 2x - 6y = 2 2x - 6y + 6y = 2 + 6y 2x= 2 +6y 2x/2 = (2+6y)/2 x= a million + 3y ----------------------- different equation 3x - 8y = 4 3*(a million + 3y) - 8y = 4 3 + 9y - 8y = 4 3 + 1y = 4 3 - 3 + 1y = 4 - 3 1y = a million y=a million. x= a million+ 3y x= a million + 3*a million x=4. verify 3x - 8y = 4 3*4 - 8*a million = 4 12-8 = 4 checks 2x - 6y = 2 2*4 - 6*a million = 2 8 - 6 = 2 checks ERGO: y = a million and x = 4.