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How can the sequence be deciphered?
The sum of the first 10 terms of an arithmetic series is 185
and the sum of its fourth and eighth terms is two times the sixth term.
2 Answers
- ?Lv 78 years agoFavorite Answer
The sum of the first 10 terms of an arithmetic series is 185.
The sum of its fourth and eighth terms is two times the sixth term.
2a + 55d = 185
Assuming d to be 3
2a = 185 - 175
2a = 10
a = 5
5, 8, 11, 14, ...
an = 3n + 2
The second sentence is of no help in solving this problem.
- Francis KLv 58 years ago
Let n be the first term and d be the difference.
The first ten terms amount to n + n+d + n+2d + n+3d +...n+9d
10n + 55d = 185
The fourth term is n+3d
The 8th term is n+7d
The 6th term is n+5d
So from the statement of the problem n+3d + n+7d = 2(n+5d)
Simplifying this 2n +10d = 2n +10d Notice that this is true for all n and all d. In other words, all arithmetic series will have the sum of the 4th and 8th terms equal to twice the 6th term. This then gives us no extra information.
Back to the earlier part:
10n + 55d = 185
Lets just try a few example values for n and for d
n = 14, d = 1
14 + 15 + 16 + 17 + 18 + 19 + 20 + 21 + 22 + 23 = 185 17+21 = 38 = 19*2
n = 5, d = 3
5 + 8 + 11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 = 185 14 + 26 = 40 = 20*2
So, there is not a single possible answer to the question.
Source(s): 50 years of math