How do I solve this math question? 10 points best answer. Urgent!!?

Let r be the common ratio. Then since the first term is 9, we know the second term is 9r, and the third term is 9r^2. But we are told that the third term is 4, so we have:

9r^2 = 4

r^2 = 4/9

r = 2/3 (not -2/3, because we are told that the common ratio is positive)

Since the second term is 9r, the second term must be 9(2/3), which is 6.

Hope that helps :)

The common ratio is 2/3... As in two thirds.

How did we find this? Well... We use this equation...

9 / x / x = 4

Which also means...

9 (1/x) (1/x) = 4

9/x^2 = 4

x^2 = 4/9

x=Squareroot(4/9)

So 9 x 2/3 = 6

The 2nd term is 6... Good luck!

you should do it by utilizing your self i basically can help you respond to A 3x + 2y = 34 5x – 2y = 30 8x = sixty 4 x = 8 (a) {7x + 3y = 75 -a million*{2x + 3y = 30 5x = 40 5 x = 9 (h) 5 * {9x – 4y = sixty 3 -4 * {14x – 5y = 109 {45x – 20y = 567 {-56x + 20y = -436 -11x = 131 x = -131/11