biology help please 10 points awarded to best answer?

Question

1. A woman who does not carry the color-blindness allele has children with a man who is color blind.
What proportion of their children will be color blind?

A) 3/4 B) all C) 1/4 D) 1/2 E) none

its 1/2 right?

2. What is the connection between sickle-cell anemia and malaria? 6)
A) Heterozygotes for sickle-cell anemia have some resistance to malaria.
B) Both are dominant.
C) Both are autosomal recessive.
D) Heterozygotes for malaria have some resistance to sickle-cell anemia.
E) Both are X-linked.

3. What is one difference between polyploidy and aneuploidy? 8)
A) Polyploidy is one extra chromosome; aneuploidy is one missing chromosome.
B) Polyploidy causes diseases and disorders in humans, aneuploidy does not.
C) Polyploidy is extra sets of chromosomes; aneuploidy does not increase by a full set.
D) Polyploidy is extra sex chromosomes; aneuploidy is extra autosomes.
E) Humans can be viable as polyploids but not as aneuploids

4. What are the characteristics of the human sex chromosomes? 12)
A) Y chromosomes are smaller in size.
B) The X chromosome carries genes required by both males and females.
C) Y chromosomes carry genes required by males only.
D) X chromosomes are larger in size.
E) All the above statements are true

5. The term for having one extra or one fewer chromosome than the standard diploid set is

6.Watson and Crick: 18)
A) were unaware that others were also seeking the structure of DNA.
B) relied heavily on the experimental results of others.
C) were hired by laboratories specifically to study DNA.
D) did extensive experimentation.
E) had strong evidence that DNA was a protein.

Roland · Accepted Answer

1. The answer is NONE.
Mother is CC, father is cY.
Children can be CY (normal boy) or Cc (normal girl).

2. D
3. C
4. E
5. aneuploidy
6. B

? · Answer

1. Heterozygous method having two different alleles. For that reason, Ff is the heterozygote. 2. The heterozygous mother or father can make F gametes and f gametes. The homozygous recessvive mum or dad can handiest make f gametes. Accordingly, making all feasible mixtures, that you could get Ff and ff offspring. 3. The punnett square would appear like: ..........F..........F.......... F........Ff..........Ff.......... F........Ff..........Ff.......... So, any baby has a 1/2 risk of being ff and a half threat of being Ff. Four. If one dad or mum is RR and one is rr, then all offspring have to get an R from one mum or dad and an r from the opposite. They all have got to be Rr. 5. Each and every baby has a three/four hazard of getting dimples. 1/four of being homozygous dominant (DD) and half of being heterozygous (Dd) ..........D..........D.......... D.......DD.......Dd......... D........Dd.......Dd.......... 6. You can use the same punnett square as for #5. Due to the fact that the moms and dads each and every have one replica of the dominant allele, they are going to show the dominant phenotype and have dark hair. Their genotype is Dd

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biology help please 10 points awarded to best answer?

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