8th grade?? math problem answer please?

5h^2 + 17h - 12 = (5h - 3)(h + 4)

A. (h + 4)

You need to crunch the possible solutions:

If its A (h+4), the only possible other factor would be (5h-3). That solution works. Do the math by multiplying (h+4) X (5h-3). You get 5h^2+17h-12.

We only need to stop there...but to make my point.

If its B (5h+3), the only other factor would be (h-4)...that gives 5h^2-17h-12

...and so on for C, D.

The trick is to look at the first set of numbers in the polynomial (5h^2). That gives you the first clue.

Then look at the last expression (-12). Then quickly crunch the multiplication to get the middle part and see if it matches (+17h)

5h^2+17h-12 = (h+4)(5h-3)

Ah^2+Bh-C

To find factors, multiply A and C = 60

Find two numbers that multiply to 60 but add up to B (which is 17)

12*5 = 60

12+5 = 17

Answer: A

Factoring this one is messy...

There's only one way to factor 5.

(5h )(h )

12 is negative so one factor will be positive and one will be negative

let's try 4 and 3 (to be honest, this is a bit of experience or trial and error and realizing you need a big positive number)

5*4=20-3=17

the 4 is positive and 3 is negative

(5h-3)(h+4)

the only match is A

Other people are simply factoring the quadratic, which I don't think is the point of this problem.

By the factor theorem, any factor of the quadratic is a root.

A) 5(-4)^2+17(-4)-12 =0 , so this is a factor.

B) 5(-3/5)^2+17(-3/5)-12 /=/0

C) 5(3)^2+17(3)-12 /=/0

D) 5(-4/5)^2+17(-4/5)-12/=/0

So A) is the answer.

All you ought to do is to function your words. Ex. the ordered pair is (3,2). you ought to work out if this is a answer. a million. x+y=5 3+2=5 upload your x and y 5=5 hence #a million is definite. 2. 2x-y=4 2*3-2=4 upload your x and y 6-2=4 4=4 Therfore #2 is a answer. as long as your numbers adventure up, this is a answer. in the event that they do no longer, they are not.