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a 15 gram coin is placed on the rim of a turntable rotating at a rate of 15RPM...?
The radius of the turntable is .25 meters. Determine:
a) the centripetal force acting on the coin
b) when the turntable's rateis ncreased to 25RPM, the coin just begins to slip off. Determine the coefficient of friction (u) between the coin & the turntable.
***please note that i converted 15rpm into 1.571 rad/sec, and 25rpm into 2.618 rad/sec (required by my professor as a first step to solve the problems) so please use the rad/sec in the work shown.
===>note: I am not sure what formula to use to find "centripetal force" i used Ac=rw^2 but then realized that is to find centripetal acceleration, not centripetal force. pls help explain what formula to use/steps to take to find this centripetal force....once i have that i know to use f (force) = (u) * n (the normal) to find the coefficient of friction
ac = rw^2 is stating that centripetal acceleration is equal to the radius times omega squared
2 Answers
- JullyWumLv 78 years agoFavorite Answer
a) Centripetal force = m x Ac = m x rω² .. .. Fc = mrω²
Fc = 0.015kg x 0.25m x (1.57 rad/s)² .. .. ►Fc = 0.009 N
b) At the point of slipping the max frictional force (μ.mg) is providing the centripetal force (mrω²) ..
μ.mg = mrω² .. .. m cancels out
μ = rω² / g .. .. 0.25m x (2.62rad/s)² / 9.80 .. .. ►μ = 0.175
- ?Lv 44 years ago
Yap, the respond is on the edge of the turntable. through fact the platter is a around plate and rotates as one device, the middle and the edge of the platter rotates on the perfect time (try drawing a right this moment line from the middle to the side. count quantity the term required for the side to make an entire around action. it would and can be the perfect term through fact the term required for the middle to make an entire around action). Now the equation for counting velocity (not velocity, as velocity hence will variety through fact the platter is going in around action. velocity is direction dependant and can have unfavorable fee) is: v = s/t the place as v=velocity, s=distance, t=time From clarification above, of course we are in a position to work out that the time is an identical between the side and the middle of the platter. the area inspite of the undeniable fact it somewhat is particularly distinctive. the side might've to commute greater distance while in comparison with the middle as a manner to make an entire around action. So in accordance to the equation, v has the perfect fee on the side. best suited velocity potential best suited centripetal rigidity (rigidity it somewhat is attempting to throw the penny off the platter). to regulate this, the penny choose best suited centrifugal rigidity (rigidity it somewhat is attempting to hold the penny from throwing off the platter).