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ツ→Cheeta★
ツ→Cheeta★ asked in Education & ReferenceHomework Help · 8 years ago

How Do I Find Stationary Points?

I found dy/dx = (2x – y)/(x + 1)

To find stationary points dy/dx = 0

So (2x – y)/(x + 1) = 0

Then I think you put 2x – y = 0

So 2x = y

Where do I go from here?

Update:

Original equation is xy + y –x^2 = 8

When I differentiate I get y + x dy/dx + 1 dy/dx – 2x = 0

Then 1 dy/dx + x dy/dx = 2x – y

Dy/dx ( x+1) = 2x – y

So dy/dx = (2x-y)/(x+1)

3 Answers

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  • ?
    Lv 5
    8 years ago
    Favorite Answer

    OK so far.

    So now

    2x = y

    and what is y?

    From your original equation, (x+1)y = x^2+8

    so y = function of x = ...

    so 2x = that functionof x

    so x = ...

    then y = ...

    for stationary points.

  • Anonymous
    8 years ago

    What's the original equation?

    Edit:

    xy + y - x² = 8

    y(x + 1) = 8 + x² ---> y = (8 + x²) / (x + 1) ---> Now you differentiate.

  • ?
    8 years ago

    go to http://www.wolframalpha.com/examples/StationaryPoi... it the eazy way.......

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