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I need Algebra help please..............?
If f(x)=x^2-5 and g(x)=6x then what is g(f(x))?
What are the roots of f(x)=x^4+4x^2-32?
Thank you...
2 Answers
- 8 years ago
the equation is gfx=0
if gx=6x then gx is 6x because 6x=6x, so g=6
you can sub in g to g(f(x))=0
you also know fx=x^2-5 so sub in x^2-5 as fx
the equation would be 6(x^2-5)=0
distribute the 6 so it would be 6x^2-30=0
move the -30 over so its 6x^2=30
divide both sides by 6 so its x^2=5
square root both sides s x=2.236067978 or x=2.24
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sorry i couldnt do the second, it takes a long time to type out and im lazy :p
Source(s): https://homeworkhelp.ilc.org/ just give them the question and theyll take you through it - 8 years ago
6(x^2-5)
6x^2-30
Factor the your second question.
(X^2 + 8)(x^2 - 4) the first set of parenthesis results in imaginary answers but you can factor the second parenthesis because it is the difference of two squares.
The real factors are: (x^2 + 8)(x+2)(x-2)