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4 wire, unbalanced star load. Please help me!?
I'm quite stuck on an assignment.
400V, 3 Phase supply, 4 wire star, 3 resistive loads of - 24kW, 18 kW, 12kW.
I need to find out the current in each line and the current in neutral conductor.
Any help on what I need to do, would be soooo great!
Thankss.
2 Answers
- billrussell42Lv 78 years agoFavorite Answer
400 volts phase to phase is 231 volts phase to neutral.
Assuming the loads are connected phase to neutral, then the currents are
24 kw/231 = 104 amps
18 kw/231 = 78 amps
12 kw/231 = 52 amps
we can add these as vectors to get the current in neutral
104 amps = 104i
78 amps = –78isin30 + 78jsin60 = –39i + 67.5j
52 amps = –52isin30 – 52jsin60 = –26i – 45 j
sum is 39i + 22.5j
magnitude is √(39² + 22.5²) = 45 amps
but check the math
- 8 years ago
Voltage per phase = 400/sqrt(3) =235 v/ph
P = V x I x pf
pf is unity for resistive loads.
Therefore,
I1 = 24000/235 = 102.13 A
I2 = 18000/235 = 76.6 A
I3 = 12000/235 = 51 A