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Solve equation with exponents of x?
Sorry, no one was answering in the Math section and this is sort of urgent (I'm helping a friend :P)
How would I go about solving this?
(1/32)^x + 3 >= 16^(3x)
2 Answers
- kasabLv 78 years agoFavorite Answer
Take the normal log of both sides,
x*log(1/32) + log3 >= 3*x*log16
-1.505*x + 0.477 >= 3.612*x
-5.117*x + 0.477 >= 0
-5.117*x >= - 0.477 , multiply through by (-1)
5.117*x >= 0.477
x >= 0.0932
- kendryLv 44 years ago
Assuming you meant (x-2)^(3/2) = sixty 4 (x-2)^3/2 = sixty 4 sq. the two factors of the equation (x-2)^3 = 4096 locate the cube root of the two factors of the equation (x-2) = sixteen upload 2 to the two factors of the equation x = 18 verify (18-2)^(3/2) = sixty 4
