Quadratic Equations: x^2+bx+c=0?

Actually the quadratic equation is as follow:

ax^2 + bx + c = 0 => don't forget the "a" it's very important!

Now:

a^2 + 10a + 24 => find two numbers that multiply to 24 , add to 10, how about 4 & 6?

=(a + 4)(a + 6)

2) same as above: 3 & 9?

3) 3 & 11?

4) find two numbers that multiply to -63, add to -2, how about 7 & -9?

= (g + 7)(g - 9)

5) try +8 & - 7?

I hope this helps.

I'll tell you the formula for this kind of equation when it can be factored.

x ^ 2 - Sx + P = 0 where S stands for the sum of the two roots and P for their product.

In (1), we have: S = -10 ; P = 24 , therefore, the roots are easily obtained as 4- and -6, and we can write:

(a+4) (a+6) = 0

In (2), we have: S = -9 ; P = -3 , therefore: (h+9) (h+3) = 0

Similarly, for 3, 4, and 5, we obtain:

3) (x+3) (x+11) = 0 ; x = -3 ; x = -11

4) (g-9) (g+7) = 0 ; x = -9 ; x = 7

5) ( w+8) (w-7) = 0 ; x = -8 ; x = 7

These are, of course special cases which can be factored in this way. The general way for solving quadratic equations is :

If ax^2 + bx + c = 0 , then: x1 = -b + SQR (b^2 - 4ac) and x2 = -b - SQR (b^2 - 4ac)

Obtain the roots of the above equations from the above general formula and compare them to the factored answers. You will see that they are the same.

What is the question that you are asking, those are all quadratic equations, do you just need to factor them?

ok...visit "wolf ram alpha" google it....find it on the site.....

http://www.wolframalpha.com/

use d method....its better

more u practice better u become!

good luck