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Please help! Physics problem.?
Hi,
Can you please help me with this rather difficult physics problem.
PS English is not my 1st language, so sorry if I make mistakes.
An object is launched horizontally from the stairs.
The Vo,x is 1,5m.s^-2
Every step is 10cm high and 10cm wide.
The steps are numbered from top to bottom.
So the top of the stairs is step 0(This is where the object is launched from)
1st step is step 1
2nd step is step 2, etc
Q. What step will the object land on?
A. 3
B. 4
C. 5
D. 6
Can you please put the entire equation, how you solved the problem.
And not just A B C or D.
Thanks for your help
@ Turn up the heat......why???
2 Answers
- rhodeLv 44 years ago
If the whole time from bounce to max top then all the way down to floor returned is two.8 s, the time to prevail in max top is a million/2 of two.8 s through symmetry of time, distance, and velocity of "loose-fall" action. d = a million/2gt² {the place d = max top, g = 9.eighty one, t = a million.4} d = (0.5)(9.eighty one)(a million.4)² = 9.6 m ANS remark: formula used is for the area = d, as ball *falls* from relax to floor in a million.4 s, and not the formula for the ball because it *rises* from bounce to max top. The formula are diverse in each case, however the respond is the comparable through fact of action symmetry.
- Anonymous8 years ago
I say, the answer is, B.
Source(s): @ Asker. I took a guess.