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Help with a pre-calc question?
The question is: 4SIN(theta) + 7 = 9 and the interval is 0- theta- 2pi. I know you simplify and end up with SIN(theta) = 1/2 and the two angles for the interval are pi/6 and 5pi/6 but what I don't understand is how you find the two angles for the interval ( the pi/6 and the 5pi/6 ). Could someone please explain this to me?
Ok I see how to get pi/6 using ARCSIN(1/2) but how do you find 5pi/6 then ?
2 Answers
- PhiloLv 78 years agoFavorite Answer
You memorize the basic facts for 30° (π/6), 45° (π/4), 60° (π/3), and 90° (π/2).
From geometry, the sides of a 30-60-90 triangle are in the ratio 1:√3:2,
and for a 45-45-90 triangle, the ratio is 1:1:√2
So for 30°, sin is ½, cos is ½√3, and tan is √3 / 3
For 60°, sin is ½√3, cos is ½, and tan is √3
For 45°, sin and cos are both ½√2, and tan is 1.
Using those as reference angles and taking the quadrant into account to get the signs right, you should know or be able to figure out very quickly all 6 trig functions for 16 different angles.
- ?Lv 58 years ago
4SIN(theta) + 7 = 9 subtract 7 from both sides
4SIN(theta) = 2 divide both sides by 4
SIN(theta) = 2/4 = 1/2
now you have to use the inverse sine function: the arcsin function, which tells you the angle whose sine is 1/2. You can use sine tables or use a calculator, to find the answers: pi/6 and 5pi/6 radians.