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Help with calculating pressure?
A deep sea diving vessel can withstand pressures up to 80MPa. Determine the maximum depth to which the vessel could descend. Take the density of sea water to be 1100kg/m^3.
It'd be great if you could explain in detail please :)
3 Answers
- Anonymous8 years agoFavorite Answer
pressure = depth*density
depth = pressure/density
since density is in kg/m^3;
convert pressure in Pacals to kg/m^2
1Pa = 0.10197 kg/m^2
80MPa = 8.1578E6 kg/m^2
then;
depth = 8.1578E6/1100
depth = 7.416 km ...... Answer
- ?Lv 78 years ago
1 Pascal = 1 kg/(meter sec²) (Wikipedia)
Pressure = density*g* depth where g is the acceleration of gravity (9. 8 meter per second²)
Think of cubes of water 1 meter x 1 meter x 1 meter stacked upon each other.
80 MPa = 8 x 10^7 kg/(meter sec²) = (1100 kg/m³)(9.8 m/s²)(depth)
depth = (8 x 10^70/((1100)(9.8)) = 7,420 meters = 7.42 km, this is about 4.61 miles
Source(s): Wikipedia - jimmymae2000Lv 78 years ago
80MPa = 11603 PSI
Specific Gravity Sea Water = 1.1
27.7 inch water column = 1 PSI, for sea water 27.7 / 1.1 = 25.18 inch
So 11603 X 25.18 = 292184 inches
292184 / 24 = 12,174.35 feet depth