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?
Lv 6
? asked in Science & MathematicsEngineering · 8 years ago

Help with calculating pressure?

A deep sea diving vessel can withstand pressures up to 80MPa. Determine the maximum depth to which the vessel could descend. Take the density of sea water to be 1100kg/m^3.

It'd be great if you could explain in detail please :)

3 Answers

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  • Anonymous
    8 years ago
    Favorite Answer

    pressure = depth*density

    depth = pressure/density

    since density is in kg/m^3;

    convert pressure in Pacals to kg/m^2

    1Pa = 0.10197 kg/m^2

    80MPa = 8.1578E6 kg/m^2

    then;

    depth = 8.1578E6/1100

    depth = 7.416 km ...... Answer

  • ?
    Lv 7
    8 years ago

    1 Pascal = 1 kg/(meter sec²) (Wikipedia)

    Pressure = density*g* depth where g is the acceleration of gravity (9. 8 meter per second²)

    Think of cubes of water 1 meter x 1 meter x 1 meter stacked upon each other.

    80 MPa = 8 x 10^7 kg/(meter sec²) = (1100 kg/m³)(9.8 m/s²)(depth)

    depth = (8 x 10^70/((1100)(9.8)) = 7,420 meters = 7.42 km, this is about 4.61 miles

    Source(s): Wikipedia
  • 8 years ago

    80MPa = 11603 PSI

    Specific Gravity Sea Water = 1.1

    27.7 inch water column = 1 PSI, for sea water 27.7 / 1.1 = 25.18 inch

    So 11603 X 25.18 = 292184 inches

    292184 / 24 = 12,174.35 feet depth

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