Kirchoff's voltage law?

Question

Ok, so according to my book (Electronics for dummies) voltage is the measurement of the difference between strength of the 'push' of electrons at one point from that of another. Simple enough so far, right?

But then along comes Kirchoff's voltage law, and that apparently states that when you start off you're at "0 voltage", then you get to your load and you 'drop voltage' leaving you at (for the sake of argument) "1.5 voltage" so that's easy to understand. What _I_ don't get is the next part, which is when the current reaches the 'end of the line' (so to speak) you're _back_ at 0. So, where did the extra 'pressure' come from?

? · Accepted Answer

Kirchhoff's voltage law states: the sum of the voltage rises (voltage sources) is equal to the sum of the voltage drops.  This is easy to understand if you think of a battery as a voltage rise and the voltage across a resistor as a voltage drop.  The part about current in your message is very confusing and not correct.  Current never reaches the end of the line, but it must flow in a complete loop.

? · Answer

examine Kirchhof's Circuit rules in Wikipedia. o.k. defined. the present regulation could be greater particularly understood in case you talk modern-day flowing to the junction as +ve and flowing out as -ve. The voltage regulation is purely all of the voltages in the circuit is +ve (in basic terms the sequence ones upload up) and that of the source is -ve. If greater advantageous than one source is asserted in sequence they upload up in the -ve.

oladapo · Answer

kirchoff'i̶̲̥̅̊s̶̲̥̅̊  voltage laws state that the total voltage flowing thru anode equal to the total voltage flowing away from the anode equal zero

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Kirchoff's voltage law?

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