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Dollar
Dollar asked in Science & MathematicsMathematics · 8 years ago

PLEASE HELP ME WITH THIS MATH QUESTION?

PLEASE SHOW YOUR WORK ON HOW TO GET THE CORRECT ANSWER

The range of g(x)= (-x^2+2x+7)^(1/2) is:

options:

a) 1≤y≤8

b) 0<y≤√8

c) 0≤y≤√8

d) 0<y<√8

3 Answers

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  • Iggy Rocko
    Lv 7
    8 years ago
    Favorite Answer

    -x^2 + 2x + 7 =

    -(x^2 - 2x) + 7 =

    -(x^2 - 2x + 1) + 8 =

    -(x - 1)^2 + 8

    The range of the above is (-∞, 8).

    Therefore, the domain of g(x) is [0, 8].

    Therefore, the range is [0, √8], or 0 ≤ y ≤ √8

  • Mike G
    Lv 7
    8 years ago

    g'(x) = (1/2)(-2x+2)/-x^2+2x+7)^(1/2) = 0 for maximum

    2x=2

    x = 1

    g(1) = sqrt(8)

    Range 0≤y≤√8

    Answer c)

  • ?
    8 years ago

    >>>>>>>>>>>>>>

    Source(s): i cannot understand this.what i have to find?
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