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Number Theory question?
If we squeezed all the real numbers between -infinity and +infinity into the little space between 0 and 1 what could we say about the number density of the new number line between 0 and 1 ?
3 Answers
- TompLv 78 years agoFavorite Answer
I started off this question, full of confidence in giving an answer to your question. After spending an inordinate amount of time deleting, rewriting, rethinking, deleting (again!), I reluctantly came to realise that I cannot give a satisfactory answer.
However, (at the risk of being shot down ignominiously in flames), I will offer this
First, I assume that we agree that the set of real numbers consists of zero-dimensional points on the number line.
Consider the function
y: R -> k
where
y(x) = k
and k is some constant.
Now, for each point x in the (open) interval ]a, b[, since the two lines y = 0 and y = k are parallel we can rightly say that
the 'length' of the line representing the interval ]a, b[ is equal to the length of the line between the points
y(a) and y(b)
That is, the lengths of the two lines are both |b - a|
But what about y = mx for some real number m?
Generally, for m<>0 the length of the line between y(a) and y(b) is
√((b - a)² + (mb - ma)²) > |b - a|
But y = mx is a bijective function.
Let m increase (negatively or positively) as much as you like.
There is still one-to-one correspondence between the intervals ]a, b[ and ]y(a), y(b)[ even though the lengths of the lines differ.
Surely this implies that there is no effect at all on the number density by 'squeezing' the set of reals into any arbitrary (open) interval ]a, b[
Or am I being naïve?
- Anonymous8 years ago
I think that the density of the numbers between 0 and 1 is the same as the density of all of the real numbers.
Look in here for further information- http://en.wikipedia.org/wiki/Cardinality_of_the_co...
- Anonymous8 years ago
You can't do that because you propose to put the infinite into the finite.