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Can someone explain how to solve this equation.?
10x - 5(sqrt(x)) - 2 = 0
3 Answers
- ranjankarLv 78 years agoFavorite Answer
Let \/x be = a
10a^2 - 5a = 2
DIVIDE BY 10
a^2 - 1/2a = 1/5
ADD 1/16
a^2 - 1/2a +1/16 = 1/5 +1/16 = 21/80
( a - 1/4) ^2 = 21/80
a = 1/4 + \/ (21/80) OR 1/4 - \/ (21/80)
a = 0.76 OR - 0.26
x = 0.07 OR 0.58 ANSWER
- 8 years ago
let us assume x=y^2
=> 10y^2 - 5y - 2=0
d = (-5)^2 - 4x10x(-2)
d = 25 + 80 = 105
y = (5 + sqrt(105)) / 20 & y = (5 - sqrt(105)) / 20
solve them and put x = y^2
- ?Lv 78 years ago
Write sqrt(x) = z
10*z^2 - 5*z - 2 = 0
Can't factor it- use method in link
z = (1/10)*(5 +- sqrt(25+4*2*10))
z = (1/10)*(5 +- sqrt(105))
z = 1.525 or z = -0.525
x = z^2 = 2.325 or x = 0.275 <<<
