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Find z if the standard normal curve area between -z and z is 0.4530?
Need help with my final three math questions please!
1) Find z if the standard normal curve area between -z and z is 0.4530
a. ± 0.118
b. ± 0.398
c. ± 0.602
d. ± 0.752
2) If a random variable has the normal distribution with μ = 104.3 and σ = 5.7, find the probability that the value will be greater than 112.3
a. 0.08
b. 0.09
c. 0.10
d. 0.11
3) Determine a 90% confidence interval for μ if σ = 5, \bar{x} = 70, and n = 82. Answer interval rounded to two decimal places.
2 Answers
- ?Lv 45 years ago
i am going to do the first one,a million) If the realm is 0.4530, then the realm > z(assuming z> 0 )will be ( a million - .4530)/2 = 0.2735 subsequently the realm < z is a million - 0.2735 = 0.7265. From tables we get z = 0.602 so c).
