Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Help with solving two equations ?!?!!!?
3x/8-2x=1/5
11x/3-1/4+3=7x/6+1/3
4 Answers
- ?Lv 58 years ago
1) 3x/8-2x=1/5 convert -2x to -16x/8
3x/8 - 16x/8 = 1/5
(3x - 16x)/8 = 1/5 multiply both sides by 40, to eliminate the denominators
5(-13x) = 8 = -65x divide both sides by -65
-8/65 = x
2) 11x/3-1/4+3=7x/6+1/3 combine like terms
11x/3 + 2 3/4 = 7x/6 + 1/3
11x/3 + 11/4 = 7x/6 + 1/3 multiply both sides by 12, to eliminate the denominators
44x + 33 = 14x + 4 subtract 14x from both sides
30x + 33 = 4 subtract 33 from both sides
30x = -29 divide both sides by 30
x = -29/30
- billrussell42Lv 78 years ago
lack of parans make both equations very ambiguous.
to take just one term: 7x/6+1/3
is that (7x/6)+(1/3)
or 7x/(6+1)/3
or 7x/(6+(1/3))
all totally different. and that is just one term.
- Mike TLv 78 years ago
3x/8 - 2x = 1/5
5 * (3x/8 - 2x) = (1/5) * 5
15x/8 - 10x = 1
8 * (16x/8 - 10x) = 1 * 8
15x - 80x = 8
-65x = 8
x = -8/65
...