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Praveen
Praveen asked in Science & MathematicsMathematics · 8 years ago

TOUGH MATHS QUESTION!!PLEASE HELP!!!?

Solve the following eqn for 0 deg <_ x >_ 360 deg.

2 cos x - sin x = 3/ 2 cos x + sin x

Please help... I really need to know this question step by step...! Thanks!

1 Answer

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    Lv 7
    8 years ago
    Favorite Answer

    ie 2sin(x) = (1/2)cos(x) oe

    tan(x) = 1/4

    x = 14.0 + 180n degs (1dp) n = 0,1,2 etc

    x = 14.0 degs or x = 194 degs in the range

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