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Find the center and radius?
How do you name the center and radius of this equation?
(x-1)^2 + (y-3)^2 = 4
2 Answers
- No MythologyLv 78 years agoFavorite Answer
The equation (x - h)² + (y - k)² = r² has a graph that is a circle of radius r centered at (h, k). Comparing this to your equation
h = 1, k = 3 and r = 2 (since r² has to be 4).
So the center is (1, 3) and the radius is 2.
- ≈ nohglfLv 78 years ago
Equation for a circle centered at the poin (h,k) with radius 'r'
(x-h)^2 + (y-k)^2 = r^2
So for
r^
(x-1)^2 + (y-3)^2 = 4
You have a center of (1,3) and a radius of 2 (since r^2 = 4 and thus r = 2)
