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Help with vectors: how do I solve this?
See attached picture link. I'm doing an online physics course, and I'm not grasping the explanation given in the video lecture. I would appreciate if someone could tell me how to solve the problem rather than just giving me the solution.
Thanks in advance.
When you say "x-component uses magnitude and cos of angle", does that mean the answer is computed with 7cos55? Because when I do that, the calculator I'm using doesn't give me what you're getting, and both the answer I get and the one you've given are being shown as incorrect.
1 Answer
- godzyxLv 68 years agoFavorite Answer
You have magnitude of vector a, | a | = 7. So you know vector is oriented 55° from x-axis. So if we make x-axis our reference, the angle will be -55°.
So you are looking for <x, y, z>. But you do not have enough info to work out three numbers, this means one is 0. Typically, angle corresponds to x and y planes, so z-component = 0.
Now this is just right triangles and basic trig (sin/cos).
x-component uses magnitude and cos of angle. y-component uses magnitude and sin.
<4.02, -5.73, 0>
Edit. Yes, x-component is 7 cos 55°.
Your calculator has to be in degree mode. As for my answers not being correct, there are a number of distinct possibilities.
Significant figures. I have 3. This has an effect on automated homework systems.
Planes. I made an assumption based on 55 clockwise from x-axis. This could be wrong. I made the z-coordinate 0. With the information provided, I believe I am correct.
- x axis. I read this as x axis. But the -x axis is 180°. So 55° CW from -x axis is 180° - 55° = 125°
7 cos 125° = -4.02
7 sin 125° = 5.73
Try:
<-4.02, 5.73, 0>