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Help with mixture question, please?
By weight, liquid A makes up 7.0 percent of solution I and 14.5 percent of solution II. If 3 grams of solution I is mixed with 2 grams of solution II, then liquid A accounts for what percent of the weight of the resulting solution?
Logic of setting it up?
2 Answers
- DWReadLv 78 years ago
"By weight, liquid A makes up 7.0 percent of solution I and 14.5 percent of solution II."
Let s₁ and s₂ be the grams of solutions 1 and 2, respectively.
"3 grams of solution I is mixed with 2 grams of solution II"
s₁ = 3
s₂ = 2
Weight of mixture = s₁ + s₂ = 5 g
0.07s₁ + 0.145s₂ = 0.21 + 0.29 = 0.50 g
The mixture contains 0.50 g of A.
0.50 g/5 g = 0.10 = 10%
A accounts for 10% of the mixture.
