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Math question. Not for homework, just fun?
Maria bought 2 cups of fruist and 3 cups of jello. She paied 49 cents. George bought, in the same store, 4 cups of fruit and 2 cups of jello. He payed 62 cents. How much is the Jello?
I am curious as to how you do the work, thanks.
2 Answers
- Anonymous8 years agoFavorite Answer
2f + 3j = 49
4f + 2j = 62
You have two lines. Where they cross, the values of x and y satisfy both equations simultaneously, so it is called a simultaneous system. There are two ways to find that point. Substitution is when you solve one equation for one variable and substitute that into the other equation.
4f + 2j = 62
2j = 62 - 4f
j = 31 - 2f Substitute this for j in the other equation.
2f + 3(31 - 2f) = 49
2f + 93 - 6f = 49
-4f = -44
f = 11 Put this into either original equation to find j.
j = 9
Elimination is when you add the equations in a way to eliminate one variable. Otherwise the process is the same.
- Iggy RockoLv 78 years ago
Let f = cost of fruit and j = cost of jello.
2f + 3j = 49
4f + 2j = 62
Solve the system of equations.
-2(2f + 3j = 49)
-4f - 6j = -98
-4f - 6j = -98
4f + 2j = 62
----------------
-4j = -36
j = 9
f = 11