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It took a crew 4 h 48 min to row 4.4 km upstream and back again. If the rate of flow of the stream was 5 km/h,?
It took a crew 4 h 48 min to row 4.4 km upstream and back again. If the rate of flow of the stream was 5 km/h, what was the rowing rate of the crew in still water?
1 Answer
- MichaelLv 78 years agoFavorite Answer
4h 48m = 4 + 48/60 = 4 4/5 = 24/5
Distance = velocity * time
time = distance / velocity
The rate of flow of the stream was 5 km/h
Velocity upstream = v - 5
Velocity downstream = v + 5
Time = time upstream + time downstream
24/5 = 4.4 /(v - 5) + 4.4 /(v + 5)
Use common denominator v^2 - 25
24/5 =( (4.4v + 22) + (4.4v - 22) ) / (v^2 - 25)
24/5 = 8.8v /(v^2 - 25)
(24/5)(v^2 - 25) = 8.8v = 44v/5
24v^2/5 - 44v/5 - 120 = 0
Solve using quadratic formula
(work not shown)
v = {-25/6, 6}
Disregard the negative root since the velocity cannot be negative
v = 6 km/h
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