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It took a crew 4 h 48 min to row 4.4 km upstream and back again. If the rate of flow of the stream was 5 km/h,?

It took a crew 4 h 48 min to row 4.4 km upstream and back again. If the rate of flow of the stream was 5 km/h, what was the rowing rate of the crew in still water?

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  • 8 years ago
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    4h 48m = 4 + 48/60 = 4 4/5 = 24/5

    Distance = velocity * time

    time = distance / velocity

    The rate of flow of the stream was 5 km/h

    Velocity upstream = v - 5

    Velocity downstream = v + 5

    Time = time upstream + time downstream

    24/5 = 4.4 /(v - 5) + 4.4 /(v + 5)

    Use common denominator v^2 - 25

    24/5 =( (4.4v + 22) + (4.4v - 22) ) / (v^2 - 25)

    24/5 = 8.8v /(v^2 - 25)

    (24/5)(v^2 - 25) = 8.8v = 44v/5

    24v^2/5 - 44v/5 - 120 = 0

    Solve using quadratic formula

    (work not shown)

    v = {-25/6, 6}

    Disregard the negative root since the velocity cannot be negative

    v = 6 km/h

    m09072013

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