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terminal potential of the battery.?
1. A battery has an Emf, ξ = 24.0 V, and an internal resistance, r = 1.50 Ω. The battery is connected to a load resistance, R = 18.0 Ω. Determine the current delivered by the battery and the terminal potential of the battery.
Can someone explain? I don't necessarily need the answer, just an explaination.
1 Answer
- TechnobuffLv 78 years agoFavorite Answer
Effectively, the circuit resistance is (18 + 1.5) = 19.5 ohms.
a) Current in circuit I = (E/R), = 24/19.5, = 1.23077A.
This current also flows through the battery, so V drop across battery's internal resistance E = (IR) = 1.23077 x 1.5, = 1.846V.
b) Battery terminal voltage under load = (24 - 1.846) = 22.154V.