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simplify: 7^(-20) - 7^(-21)?
please tell me a way to do this sum..........use rules of indices if possible
7 Answers
- RogueLv 78 years ago
7^-20 - 7^21
given a^-n = 1/a^n
=> 1/7^20 - 1/7^21
=> (1/7^20 *7/7^1) - 1/7^21
given a^n * a^m = a^(n m)
=> 7/7^21 - 1/7^21
=> 6/7^21
=> 6/558545864083284007
Source(s): http://mathematicsi.com/rules-of-indices/ - kritty karnaLv 58 years ago
7^(-20) - 7^(-21)
= 1/ {7^20} - 1/(7^21)
=(1* 7^21) - 1} / 7^21
=(7^21 -1) / 7^21
= {7^21 - (7^0)} /7^21 [a^0 =1,then 7^0=1 ]
= {7^(21-0)} / 7^21
= 7^21 /7^21
=1
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- Anonymous7 years ago
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- 8 years ago
7 ⁻²⁰ â 7 ⁻²¹
=7⁻²⁰(1 â 7 ⁻¹ )
=7⁻²⁰(1 â 1/7)
=7⁻²⁰(6/7)
=6Ã7⁻²¹(Ans)