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if I roll nine dice, what is the probability of getting three sixes (with calculations please).?

also, do the same with D20 dice instead of D6 dice

Update:

made my own script at

topps.diku.dk/torbenm/troll.msp calculator.

"

\ How many 20s when rolling 9 D20

sum 9#choose{0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1}

"

gives 0.77% or 1:129 for 3 20s using 9D20

Update 2:

edit:

looks like you got the same as my script with

"D20

------

9c6*19^6/20^9 = 0.0077 "

but can you explain what the c, the * and the ^ stand for. Or expand it into sentences instead of nomenclature

3 Answers

Relevance
  • M3
    Lv 7
    8 years ago
    Favorite Answer

    D6

    ----

    9c6*5^6/6^9 = 0.1302 <------

    D20

    ------

    9c6*19^6/20^9 = 0.0077 <----- qed

    your AD

    -----------

    9c6 = 9 choose 6, ie choose any 6 from 9 with the formula nCk = n!/(k!(n-k)!),

    9c6 = 9!/(6!3!) = 84

    and ^ has been used as the symbol for exponentiation

    eg 19^6 = 19 x 19 x 19 x 19 x 19 x 19

  • 8 years ago

    1/6 x 1/6 x 1/6

  • ?
    Lv 6
    8 years ago

    9C3(1/6)^3(5/6)^6=.130238102

    20C3(1/6)^3(5/6)^17=.237886566

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