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Please Help me with this College algebra problem, I'm Stuck :(?

Write the standard form of the equation for the line that passes through the points (-11,-4) and (-11,10).

Update:

it has to be written in the standard FORM of the equation~

4 Answers

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  • ?
    Lv 7
    8 years ago

    equation for the line that passes through the points (-11,-4) and (-11,10)

    slope m = (10 - -4)/(-11 - -11) = 14/0 = undefined

    This is a vertical line crossing the x-axis at x = -11

    The equation of the line is x = -11

  • 8 years ago

    Your answer would be X = -11 because when you solve for the slope which is m equals y 2 minus y 1 divided by x 2 minus x 1 you get 14/0. Your line is vertical and has an infinite or so called undefined slope. It is this way because you got 14/0, and it is impossible to divide by zero to find m. In this case, the equation of your line doesn't even use y=mx+b. Instead, the equation of the line is X = -11.

    Source(s): Already completed College Algebra in 12th grade.
  • 8 years ago

    First find the slope of the line with the formula,

    m=(y2-y1)/(x2-x1)

    m=(10-(-4))/(-11-(-11))

    m=(14/0)

    which is no solution

    the answer is no slope if you are asking about the slope. Next to find the equation,

    y-y1=m(x-x1)

    y-10=(14/0)(x+11)

    x=-11

  • 8 years ago

    x = -11

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