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Please Help me with this College algebra problem, I'm Stuck :(?
Write the standard form of the equation for the line that passes through the points (-11,-4) and (-11,10).
it has to be written in the standard FORM of the equation~
4 Answers
- ?Lv 78 years ago
equation for the line that passes through the points (-11,-4) and (-11,10)
slope m = (10 - -4)/(-11 - -11) = 14/0 = undefined
This is a vertical line crossing the x-axis at x = -11
The equation of the line is x = -11
- 8 years ago
Your answer would be X = -11 because when you solve for the slope which is m equals y 2 minus y 1 divided by x 2 minus x 1 you get 14/0. Your line is vertical and has an infinite or so called undefined slope. It is this way because you got 14/0, and it is impossible to divide by zero to find m. In this case, the equation of your line doesn't even use y=mx+b. Instead, the equation of the line is X = -11.
Source(s): Already completed College Algebra in 12th grade. - 8 years ago
First find the slope of the line with the formula,
m=(y2-y1)/(x2-x1)
m=(10-(-4))/(-11-(-11))
m=(14/0)
which is no solution
the answer is no slope if you are asking about the slope. Next to find the equation,
y-y1=m(x-x1)
y-10=(14/0)(x+11)
x=-11