Help me with this college algebra problem, I dont understand these :(?

General Equation of a Line is

y = mx + c................This is equation 1

m is slope

to find m

m= (y2-y1)/(x2-x1)

m = (3-(-4)) / (5-(-12))

m = 7/17

now plug in m and one of the two points back into Equation 1

3 = 5(7/17) + c

multiply equation by 17 and solve for c

51 = 35 + 17c

17c=16

c = 16/17

your final equation for this line is

y = (7/17)x + 16/17

M= Y2 - Y1/ X2 - X1

M= 3 - (-4) / 5 - (-12) = 7/17X Your slope is 7/17

Y=7/17x+B

Now, you have to find B!

You find B by using Y=Mx+B equation and inserting the slope and one of the points.

I am going to show you using the point (5,3)

Y=7/17x + B

3 = 7/17(5) + B

3 = 2.05 + B

- 2.05

1.05 = B

Your equation would be Y= 7/17x + 1.05!

The equation of the straight line joining (x1,y1) and (x2,y2) is given by (y-y1)/(y1-y2) = (x-x1).(x1-x2).

=> (y+4)/(-4-3) = (x+12)/(-12-5)

=> (y+4)/-7 = (x+12)/-17

=> -17(y+4) = -7(x+12)

=> 7x-17y =-16.

think it's 3