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Statistics problem, any help?
A certain type of thread has a mean tensile strength of 78.3 kg, with a standard deviation of 5.6 kilograms. How is the variance of the sample mean changed when the sample size is increased from 64 to 196?
Not entirely sure what this question is asking, can anyone help?
1 Answer
- paramvenuLv 78 years agoFavorite Answer
Variance (V) of the sample mean = sigma^2/n
When n = 64,
V = 5.6^2/64 = 0.49
When n = 196,
V = 5.6^2/196 = 0.16
When n value increases variance of the sample mean will decrease.
