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how do i find the intercepts of this equation?
f(x)=x^2+34x
1 Answer
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- ?Lv 48 years ago
x-intercept
Change y=0
0=x^2+34x
-34x=x^2 (subtract 34 from both sides)
x=sqrt(-34) to get rid of the x^2 into x,sqrt both sides. sqrt= square root
y-intercept
change x=0
y=0^2+34(0)
y=0
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