The sum of three intergers is 76. The sum of the first and second integers exceeds the third by 32.?

x + y + z = 76______________1

(x + y) - z = 32_____________2

z = x - 4__________________3

Substitute for z in 1:-

2x + y = 80________________4

Substitute for z in 2:-

(x + y) - (x - 4) = 32

y + 4 = 32

y = 28

2x + 28 = 80

2x = 52

x = 26

26 + 28 + z = 76

z = 22

x = 26 , y = 28 , z = 22

a + b + c = 76

a + b = c + 32

c = a - 4

Substitute the third equation in the first and second equations

a + b + a - 4 = 76

a + b = a - 4 + 32

The second of these two imply b = 32 - 4 = 28

And the first one implies 2 a + b = 80, so 2 a = 80 - b = 80 - 28 = 52, therefore a = 52/2 = 26

Finally c = a - 4 = 26 - 4 = 22

So, (a,b,c) = (26, 28, 22)