A car is to average 60 mph for two laps of a one mile oval track.?

The car can never go fast enough to average 60 miles per hour over the two miles.

It would take 1/30 hour to complete two laps at 60 miles per hour.

It takes 1/30 hour to complete the first lap at 30 miles per hour.

The car has already used up all its allotted time.

So total distance for two laps = 2 miles

Average speed = (Total distance)/(Total time)

So therefore: (2 miles)/(1/30 + 1/s) = 60 mph where s represents the average speed on the second one mile lap:

2 = 2 + 60/s => It's obvious now that this is not possible. No matter how fast the car goes on the second lap, it will NEVER have an average speed of 60 mph for the two laps.

The 1st lap was run in an average time of 2 minutes...

t = D/velocity = 1/30 hr = 2 mins.

To average 60 for 2 laps the car must complete the two miles in 2 minutes ... since he took 2 minutes to do the first lap he can NEVER recover and make the two laps in an average speed of 60mph ...

Seems weird ... doesn't it ??

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RE :A car is to average 60 mph for two laps of a one mile oval track.?

The average speed for the first one mile lap is 30 mph. What must be average speed for the second one mile lap in order to have an average speed of 60 mph for the two laps ?

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Hello!! You've answered my maths question, I've edited it to say how I've did it - please can you go back to my question please....!!!

Thank you ever so much. I've a maths test in a few days so I really need help!

Oops, sorry to say I don't know the answer to your question.