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9th Grade Point Slope problem?
♥♥♥J♥♥♥ asked just now -
4 days left to answer
9th grade Algebra:
(15, -10) , (21, -10)
-10-10
over
21-15
then -20
over
5
Then the slope is -4
Then for point slope, can someone show me how to reduce it, and show me how to get the final product?
Like put it in Point Slope form and show me how to do it.
I don't understand where I went wrong with the slope, could you explain?
2 Answers
- BattleaxeLv 78 years agoFavorite Answer
(15, -10) , (21, -10)
m = (y2 - y1)/(x2 - x1) = (-10 - (-10))/(21 - 15) = 0/6 = 0
using point (15, -10):
y - y1 = m(x - x1)
y + 10 = 0(x - 15) in point-slope form
y = 10 (horizontal line)
- .--
- hayharbrLv 78 years ago
Hold on; the top of the slope fraction is -10 - (-10) which is -10 + 10 = 0
so the slope is 0
which means its equation is just y = -10
But using point slope and point (15, -10) you'd have
y - -10 = 0(x - 15)
y + 10 = 0
y = -10
