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Help solve this math problem please....?
Just an approximate answer is all I am after... any description of how to do this would be awesome.
388960 = 0.00
388470 = 140.00
388110 = 245.00
387450 = 440.00
386290 = 785.00
383530 = 1625.00
382860 = 1830.00
200000 = ???
100000 = ???
50000 = ???
25000 = ???
1 = ???
had an offer from someone to solve my problem for money....
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kind of ruins the spirit of yahoo answers doesn't it?
however I managed to plot the arc using CAD, and at 200,021.736 the arc changes direction, hence a value for all the numbers down to 1 is impossible...
the first column is speed(MPH) , the second column is time(seconds)
1 Answer
- Julius NLv 77 years agoFavorite Answer
Data: (382860, 1830), (383530, 1625), (386290, 785), (387450, 440), (388110, 245), (388470, 140), (388960, 0)
n= 7; Σx= 2705670; Σx²= 1045842701700; Σx³= 404271026050736960; Σx^4= 1.562764405901268e+23
Σy= 5065; Σxy = 1947058450; Σy²= 6878975; Σx²y = 748495276439500
Σlog(y)= 38.1007; Σx*log(y) = 14699590.7792; Σlog²(y)= 247.2554
Linear regression: y = -11439/38038x +7318035581/62568 = -0.3007x +116961.3154
r^2= 0.9999; t= 273.93213; α = P(x>103.53660) = P(t>273.93213)=0; d.f.=5
predicted
(25000, 109443.1756), (50000, 101925.0359), (100000, 86888.7564),
(200000, 56816.1973) (1, 116961.0147)