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How do I answer these integration questions? 10points for best answer?
I need help with these questions. Please explain in detail.
1. I = ∫(x - 2x^4) dx
2. I = ∫(4x-3)^5 dx
3. I = ∫se^1-3x dx
I greatly appreciate your answers.
1 Answer
- anonymousLv 77 years agoFavorite Answer
** Naturally it is impossible to give details about the integration power rule and how u-substitutions work on a small Yahoo Answers screen. **
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1. Split it into two integrals and use the integration power rule. These are indefinite integrals and hence you need to add a constant of integration C at the end.
∫(x - 2x^4) dx
= ∫ x dx - ∫2x^4 dx
= (x^2 / 2) - (2x^5 / 5) + C
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2. Use a u-substitution.
u = (4x - 3)
du = 4 dx
Then rewrite the integral as follows:
∫(4x - 3)^5 dx
= (1/4) * ∫ [(4x - 3)^5 * 4] dx
= (1/4) * ∫ u^5 du
then it's the integration power rule
= [(1/4) * (u^6 / 6)] + C
= [(1/24) * u^6] + C
and then finally switching back to x as the variable
= [(1/24) * (4x - 3)^6] + C
** If you differentiate the above answer, you get (4x - 3)^5 **
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3. This one isn't really decipherable as written. What is se? and what is se^1-3x ?
I'm just not 'getting' what that power is. Is it sec^(1 - 3x)?