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Jared
Lv 7
Jared asked in Science & MathematicsMathematics · 7 years ago

Question on the ratio test for series convergence?

So I recently answered a question on series convergence: http://answers.yahoo.com/question/index;_ylt=Avx5N...

If you apply the ratio test, then the limit approaches 1 and the test is inconclusive. However, from an intuitive standpoint, this series should converge (see my comparison test) which shows that the exponents essentially differ by 2 and thus it should converge by the p-series test. But if you look at the result for the ratio test: you get the following limit:

lim_{x --> ∞} n^(n + 1) / (n + 1)^(n + 1)

This does indeed converge to 1 (the limit) and thus the ratio test is inconclusive. HOWEVER, it approaches 1 from the "bottom". That is, it's ALWAYS < 1 until you actually get to n = ∞. If you can show that the the limit approaches 1 from the bottom (always from the bottom) can this break the indeterminance of the ratio test? Or conversely if the limit approaches 1 from the top, can you say that the series definitely diverges?

Update:

@kb - you are correct, the ratio test does work in this case. I incorrectly took (or really didn't take) the limit.

1 Answer

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  • kb
    Lv 7
    7 years ago
    Favorite Answer

    Are you sure about this?

    lim(n→∞) n^(n+1) / (n+1)^(n+1)

    = lim(n→∞) 1 / [(n+1)^(n+1) / n^(n+1)]

    = lim(n→∞) 1 / [(n+1)/n]^(n+1)

    = lim(n→∞) 1 / (1 + 1/n)^(n+1)

    = lim(n→∞) [1/(1 + 1/n)^n] * [1/(1 + 1/n)]

    = 1/e * 1, using the limit definition of e with the first factor

    = 1/e.

    I hope this helps!

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