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Lv 5
? asked in Education & ReferenceHomework Help · 7 years ago

Factoring polynomials + zero product principle?

Original problem:

64y^3 - 2 = y - 128y^2

I turned it into

64y^3 - 2 - y + 128y^2 = 0

(64y^3 - y) + (128y^2 - 2) = 0

y(64y^2 - 1) + 2(64y^2 - 1) = 0

(64y^2 - 1) (y+2) = 0

I don't know what to do now. I'm supposed to solve it by factoring and then using the zero-product principle.

1 Answer

Relevance
  • 7 years ago

    (64y^2 - 1) (y+2) = 0

    use difference of squares rule

    (8y + 1)(8y - 1)(y + 2) = 0

    so 8y + 1 = 0, 8y - 1 = 0, or y + 2 = 0

    y = -1/8, +1/8, or -2

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