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... asked in Science & MathematicsMathematics · 7 years ago

I need help with a vectors question?

A force of (3i + 5j) N and another of (-6i – j)N act on a particle. What additional force must be applied if the particle is to remain in equilibrium?

I have no idea how to answer this. Thanks.

3 Answers

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  • ?
    Lv 7
    7 years ago
    Favorite Answer

    Sum of forces => (3i + 5j) + (-6i - j)

    => -3i + 4j

    Let the third force be ai + bj, then we have,

    ai + bj + (-3i + 4j) = 0i + 0j

    => (a - 3)i + (b + 4)j = 0i + 0j

    so, a - 3 = 0 and b + 4 = 0

    i.e. a = 3 and b = -4

    => additional force is 3i - 4j Newtons

    :)>

  • anordtug
    Lv 6
    7 years ago

    Then you must find the opposite Power to the sum of the two Powers.

    (3i+5j)+(-6i-j)=(-3i+4j)

    Therfore the Third Power must be -(-3i+4j)=(3i-4j)

  • Como
    Lv 7
    7 years ago

    F1 = - 3i + 4j

    F2 = 3 - 4j

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