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Diketahui kerucut dengan jarijari alas berukuran 5cm dan tinggi 12cm. luas permukaan kerucut tersebut adlh?
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- 7 years agoFavorite Answer
luas alas (lingkaran) = 3,14 * 5 * 5 = 78,5
alas segitiga = keliling lingkaran = 2 * 3,14 * 5 = 31,4
tinggi segitiga = √ (12^2 + 5^2) = 13
luas segitiga = 0,5 * 31.4 * 13 = 204.1
luas permukaan = 78,5 + 204,1 = 282,6
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