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Suppose an object is dropped from a height h0 above the ground.?
Need help solving this problem and help if I ever see it again!!!!!
Suppose an object is dropped from a height h0 above the ground. Then its height after t seconds is given by h = −16t 2 + h0, where h is measured in feet. Use this information to solve the problem.
A ball is dropped from the top of a building 78 ft tall. (Round your answers to three decimal places.)
(a) How long will it take to fall half the distance to ground level?
t = . sec
(b) How long will it take to fall to ground level?
t = . sec
1 Answer
- AaronLv 57 years ago
So first you have your formula and we know that h0 is 78. So your equation will look like h1=-16t^2+78. If you understand what the graph of a parabola looks like, this will make more sense.
a. Half the distance of 78 is 39. So you would set h1 = 39. 39=-16t^2+78. -39=-16t^2 t^2 = 39/16 so t≈1.56 seconds.
b. the h1 will be 0 since it's ground level. 0=-16t^2+78 -16t^2=-78 t^2=78/16 and t≈2.2 seconds.
