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wana bigger bike
Lv 6
wana bigger bike asked in Science & MathematicsMathematics · 7 years ago

factoring on Ti 89 titanium?

I am trying to factor

9x^2+6x+4

When I do factor(9x^2+6x+4)

it gives me

9(x^2+.667x+.4444)

Thats fine and all but I want it to fully factor it all, how do I make it factor the (...) part?

Im also well aware that this is an irreducible factorization but I would like it in terms of i if at all possible. Sure makes Diff-Eq homework easier. Anyone help?

3 Answers

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  • llaffer
    Lv 7
    7 years ago

    That expression doesn't factor. The zeroes of that expression are imaginary.

  • JOS J
    Lv 7
    7 years ago

    (x - 1/3 (1 + i Sqrt[3])) (x - 1/3 (1 - i Sqrt[3]))

  • wana bigger bike
    Lv 6
    7 years ago

    It does factor you just use "I" for the imaginarys. Otherwise idk how to do this diff eq qork

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