Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Three identical point charges in an equilateral triangle.?
Q = +3uC
What are the magnitude and direction of the net electric force on the charge in the lower left side. The side of the triangle is 0.1 m.
1 Answer
- oldschoolLv 77 years agoFavorite Answer
First determine the directions of the fields at the lower left vertex:
The field due to the top charge is at 240°
The field due to the charge at the lower right is at 180°
The magnitudes of the fields are the same E = kQ/r² = 2,696,266N/C
Sum the horizontal components:
Ex = Ecos240 + Ecos180 = -4,044,398 N/C
Sum the vertical components:
Ey = Esin240 + Esin180 = -2,335,034 N/C
Magnitude = √Ex²+Ey²) = 4,670,069 N/C at arctan(-2,335,034/-4,044,398) = 210°
F = qE = 14N at 210°
