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find all the values of x that satisfy the equation cos(x)=sin(x) over the interval [o,2pi]?
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- ?Lv 77 years ago
Divide both sides by cos x to get 1 = (sin x)/cos x) i.e. tan x = 1. Tan is +ve in quads I & III, and the acute angle = pi/4 so the other one is pi + pi/4 5pi/4
Source(s): Retired Maths Teacher - RamonLv 77 years ago
cos(x)=sin(x)
cos(x)/sin(x)=1
cot(x)=1
x=acot(1)
x=0.785 rad
x=45°
and
x=3.927 rad
x=225°
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