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find all the values of x that satisfy the equation cos(x)=sin(x) over the interval [o,2pi]?

2 Answers

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  • ?
    Lv 7
    7 years ago

    Divide both sides by cos x to get 1 = (sin x)/cos x) i.e. tan x = 1. Tan is +ve in quads I & III, and the acute angle = pi/4 so the other one is pi + pi/4 5pi/4

    Source(s): Retired Maths Teacher
  • Ramon
    Lv 7
    7 years ago

    cos(x)=sin(x)

    cos(x)/sin(x)=1

    cot(x)=1

    x=acot(1)

    x=0.785 rad

    x=45°

    and

    x=3.927 rad

    x=225°

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